Question 4(iii)
Identify the greater number, wherever possible, in each of the following:
(iii) $2^{8} o r 8^{2}$

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Solution

(iii) $2^{8} = 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 = 256$
$8^{2} = 8 \times 8 = 64$
Since, $256 > 64$
Thus, $2^{8}$ is greater than $8^{2}$ .

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