Question

Question 4(iii)
Identify the greater number, wherever possible, in each of the following:
(iii) $2^{8}or{8}^2$

Answer 1

(iii) $2^8=2\times 2\times 2\times 2\times 2\times 2\times 2\times 2=256$
$8^2=8\times 8=64$
Since, $256>64$
Thus, $2^8$ is greater than $8^2$.