I II
$O C l_{2}$ $O F_{2}$
The bond angle is greater in $O C l_{2}$ than in $O F_{2}$ because there is some $π$ interactions in $O C l_{2}$ involving donation from the filled p-orbitals on oxygen into the empty d-orbitals on chlorine No $π$ -bonding is possible for $O F_{2}$ because all orbitals are filled on both atoms.
If true enter 1, else enter 0.

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Solution

The bond angle between a single bond and a multiple bond is higher than the bond angle between two single bonds due to electron electron repulsion.
The bond angle is greater in $O C l_{2}$ than in $O F_{2}$ because there is some $π$ interactions in $O C l_{2}$ involving donation from the filled p-orbitals on oxygen into the empty d-orbitals on chlorine No $π$ -bonding is possible for $O F_{2}$ because all orbitals are filled on both atoms.
The statement is true. Hence, the answer is 1.

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