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Byju's Answer
Standard VIII
Mathematics
Algebraic Identities
iii Using ide...
Question
Question 6(iii)
Using identities, evaluate:
102
2
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Solution
102
2
=
(
100
+
2
)
2
=
(
100
)
2
+
2
×
100
×
2
+
(
2
)
2
[
U
s
i
n
g
i
d
e
n
t
i
t
y
(
a
−
b
)
2
=
a
2
−
2
a
b
+
b
2
]
=
10000
+
400
+
4
=
10404
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