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Question 9 ii...

Question

Question 9 (iii)

Which is greater in each of the following:
$\frac{- 3}{4}, \frac{2}{- 3}$

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Solution

$\frac{- 3 \times 3}{4 \times 3} = \frac{- 9}{12} a n d \frac{2 \times (- 4)}{- 3 \times (- 4)} = \frac{- 8}{12}$
Since, $\frac{- 9}{12}$ < $\frac{- 8}{12}$
Therefore, $\frac{- 3}{4}$ < $\frac{2}{- 3}$

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Which is greater in each of the following:
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Which is greater in each of the following?

(i) $\frac{2}{3}, \frac{5}{2}$

(ii) $\frac{- 5}{6}, \frac{- 4}{3}$

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(v) $- 3 \frac{2}{7}, - 3 \frac{4}{5}$

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