Iii Work out the following divisions 10y6y-21- 52y-7

Name: NCERT - Grade 08 - Mathematics - Factorisation - Q11_3
Uploaded: 2022-07-04T10:36:42+05:30
Description: 10y(6y+21)÷ 5(2y+7)=2× 5× y[2× 3× y+3× 7]/5(2y+7) =2× 5× y× 3(2y+7)/5(2y+7)=6y ...

10y(6y+21)÷ 5(2y+7)=2× 5× y[2× 3× y+3× 7]/5(2y+7) =2× 5× y× 3(2y+7)/5(2y+7)=6y ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VIII

Mathematics

Division of a Polynomial by a Polynomial

iii Work out ...

Question

Question 3(iii)
Work out the following divisions
$10 y (6 y + 21) \div 5 (2 y + 7)$

Open in App

Solution

$10 y (6 y + 21) \div 5 (2 y + 7) = \frac{2 \times 5 \times y [2 \times 3 \times y + 3 \times 7]}{5 (2 y + 7)} = \frac{2 \times 5 \times y \times 3 (2 y + 7)}{5 (2 y + 7)} = 6 y$

Suggest Corrections

Similar questions

Q. Work out the following divisions:

10 y (6 y + 21) \div 5 (2 y + 7)

10 y (6 y + 21) \div 5 (2 y + 7)

Q. Evaluate

10 y (6 y + 21) \div 5 (2 y + 7)

10 y (6 y + 21) \div 5 (2 y + 7)

= _________.

Work out the following divisions.

(i) (10x − 25) ÷ 5

(ii) (10x − 25) ÷ (2x − 5)

(iii) 10y(6y + 21) ÷ 5(2y + 7)

(iv) 9x²y²(3z − 24) ÷ 27xy(z − 8)

(v) 96abc(3a − 12)(5b − 30) ÷ 144(a − 4) (b − 6)

Join BYJU'S Learning Program

Explore more

Division of a Polynomial by a Polynomial

Standard VIII Mathematics

Join BYJU'S Learning Program

Question 3(iii) Work out the following divisions 10y(6y+21)÷5(2y+7)

10y(6y+21)÷5(2y+7)=2×5×y[2×3×y+3×7]5(2y+7)=2×5×y×3(2y+7)5(2y+7)=6y

Question 3(iii)
Work out the following divisions
$10 y (6 y + 21) \div 5 (2 y + 7)$

$10 y (6 y + 21) \div 5 (2 y + 7) = \frac{2 \times 5 \times y [2 \times 3 \times y + 3 \times 7]}{5 (2 y + 7)} = \frac{2 \times 5 \times y \times 3 (2 y + 7)}{5 (2 y + 7)} = 6 y$