Question

Question 2 (iii)
Write a Pythagorean Triplet whose one member is:

16

Answer 1

There are three numbers $2m,m^2-1and{m}^2+1,$ in a Pythagorean Triplet$(for,m>1)$.

$Here,2m=16\Rightarrow m=\frac{16}{2}=8\therefore \text{Second number}(m^2-1)=(8{)}^2-1=64-1=63\text{And third number}(m^2+1)=(8{)}^2+1=64+1=65$

Hence, Pythagorean triplet is (16, 63, 65).