Question

Illustrate the law of definite proportions from the following data:-1)0.32g of sulphur on burning in air produced 224ml of SO2 at N.T.P

Answer 1

S + O2 => SO2
1 mol (32g) of Sulphur produces 1 mol (64g) of sulphur dioxide.

then 0.32 g (0.01 mol) will produce 0.64 g (0.01 mol) SO2
Again 1 mol of gas occupies 22.4 litr volume. therefore 0.01 mol (0.64 g) will occupy 0.224 lit (224 ml)