Images of an object that is equidistant from the two plane mirrors whose reflecting surfaces make an angle of $90^{\circ}$ with one another lie on a/an

straight line

No worries! We‘ve got your back. Try BYJU‘S free classes today!

parabola

No worries! We‘ve got your back. Try BYJU‘S free classes today!

circle

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

ellipse

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C circle

By applying the concept of object distance $=$ image distance from the plane mirror, we can see that $3$ images and the object are symmetrical $w . r . t$ intersection of the mirrors $M_{1}$ and $M_{2}$ . Therefore, all the $3$ images lie on a circle with centre at intersection of the mirrors.

Suggest Corrections

Similar questions

Q. Images of an object that is equidistant from the two plane mirrors whose reflecting surfaces make an angle of

90^{\circ}

with one another lie on a/an

Q. Images formed by an object placed between two plane mirrors whose reflecting surfaces make an angle of

90^{o}

with one another lie on:

Q. Images formed by an object placed between two plane mirrors whose surfaces make an angle of

90^{o}

with one another lie on a

Two plane mirrors are inclined to one another at an angle of $40^{\circ}$ . A point object is placed in between them. The number of images formed due to reflection at both mirrors is

The reflecting surface of two mirrors make an angle of 90° with each other. If a ray incident of one mirror has an angle of incidents of 30°, draw the ray reflected from the second mirror. What will be its angle of reflection?

Join BYJU'S Learning Program

Images of an object that is equidistant from the two plane mirrors whose reflecting surfaces make an angle of 90∘ with one another lie on a/an

Images of an object that is equidistant from the two plane mirrors whose reflecting surfaces make an angle of $90^{\circ}$ with one another lie on a/an