Images of an object that is equidistant from the two plane mirrors whose reflecting surfaces make an angle of $90^{\circ}$ with one another lie on a/an

straight line

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parabola

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circle

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ellipse

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Solution

The correct option is C circle

By applying the concept of object distance $=$ image distance from the plane mirror, we can see that $3$ images and the object are symmetrical $w . r . t$ intersection of the mirrors $M_{1}$ and $M_{2}$ . Therefore, all the $3$ images lie on a circle with centre at intersection of the mirrors.

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Images of an object that is equidistant from the two plane mirrors whose reflecting surfaces make an angle of 90∘ with one another lie on a/an

Images of an object that is equidistant from the two plane mirrors whose reflecting surfaces make an angle of $90^{\circ}$ with one another lie on a/an