Question

Imagine a Carnot engine that operates between the temperatures $T_H$ 850 K and $T_L$ 300 K. The engine performs 1200 J of work each cycle, which takes 0.25 s. What is the efficiency of this engine?

• A. $\frac{11}{19}$
• B. $\frac{11}{17}$
• C. $\frac{8}{19}$
• D. $\frac{6}{17}$

Answer 1

The correct option is B

$\frac{11}{17}$

The efficiency of the engine can be calculated by the formula in the hint

$\eta =1-\frac{300}{850}$

$=1-\frac{6}{17}=\frac{11}{17}$