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Byju's Answer
Standard XII
Physics
Spring Block's Time Period
Imagine a nar...
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Imagine a narrow tunnel between the two diametrically opposite points of the earth. A particle of mass m is released in this tunnel. The time period of oscillation i
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Q.
If a straight tunnel is bored connecting two points on the surface of the earth, then the time taken by a particle released from any point of the tunnel, to come to instantaneously rest again in the tunnel is
Q.
A particle of mass
50
kg
thrown into the tunnel from point
A
inside the earth, the tunnel is
d
away from the center of the earth. A particle oscillates about a point
C
inside the tunnel due to the gravitational force towards the centre. Calculate the time period of oscillation. (Radius of earth
=
6.378
×
10
6
m
)
Q.
A smooth and bottomless tunnel is dug through the centre of earth. A particle is released from the surface of earth into the tunnel. Time to reach centre of tunnel is (approximately) equal to (where
R
=
Radius of earth).
Q.
Assume that a tunnel is dug along a chord of the earth, at a perpendicular distance
(
R
2
)
from the earth's centre, where
R
is the radius of the Earth. The wall of the tunnel is frictionless. If a particle is released in this tunnel, it will execute a simple harmonic motion with a time period:
Q.
A tunnel is dug along the diameter of the earth. Two balls of mass
m
and
2
m
are dropped from the opposite ends of the tunnel simultaneously. They collide in the tunnel and stick to each other. If the new amplitude of their oscillation is
R
n
where
R
is earth's radius, then the value of
n
is
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