1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# Imagine a planet having the same density as that of the earth but radius is three times the radius of the earth. If acceleration due to gravity on the surface of the earth is g and that on the said planet is g', then

A
g=g9
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
g=9g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
g=g27
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
g=3g
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

## The correct option is C g′=3gThe acceleration due to gravity on earth's surface isg=GMR2g=GρVR2 ................................................(1)Where, G is the gravitational constant, M is mass of earth, R is radius of earth, ρ is the density and V is the volume of earth.V=4/3×π×R3Putting this value in (1), we getg∝Rgg′=R3R∴g′=3g

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Variation in g
PHYSICS
Watch in App
Join BYJU'S Learning Program