Imagine that modern periodic table consists of eight periods and if there are three possible values of spin quantum number then maximum number of elements in the a $8^{t h}$ period of the long form of periodic table, will be:

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Solution

The correct option is C 75
In the $8^{t h}$ period, the electrons will be filled in 8s, 5g, 6f, 7d and 8p orbitals (as per Aufbau rule).

So from filling 8s we will get 3 elements.

After filling 5g we will get 27 more elements.

After filling 6f we will get 21 more elements.

After filling 7d we will get 15 more elements.

After filling 8p we will get 9 more elements.
So, maximum number of elements will be $= 3 + 9 + 15 + 21 + 27 = 75$ .

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Imagine that modern periodic table consists of eight periods and if there are three possible values of spin quantum number then maximum number of elements in the a 8th period of the long form of periodic table, will be:

Imagine that modern periodic table consists of eight periods and if there are three possible values of spin quantum number then maximum number of elements in the a $8^{t h}$ period of the long form of periodic table, will be: