Impossible orbital among the following is :

2 s

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3 f

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2 p

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4 d

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Solution

The correct option is B $3 f$
Impossible orbital among the following is $3 f$ .

For principal quantum number, $n = 3$ , the permissible value of the azimuthal quantum number l are 0,1 and 2 only. For $f$ subshell, the value of the azimuthal quantum number is 3.

Hence, $3 f$ orbitally is impossible.

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Impossible orbital among the following is :

The correct option is B 3fImpossible orbital among the following is 3f. For principal quantum number, n=3, the permissible value of the azimuthal quantum number l are 0,1 and 2 only. For f subshell, the value of the azimuthal quantum number is 3. Hence, 3f orbitally is impossible.