Impure copper containing Fe, Au, Ag as impurities is electrolytically refined. A current of 140 A for 482.5s and decreased the mass of the anode by 22.26 g and increased the mass of cathode by 22.011 g percentage of iron in impure copper is (given molar mass Fe = 55.5 g / mol; molar mass of Cu = 63.54 g/mol)

0.95

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0.85

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0.97

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0.9

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Solution

The correct option is D 0.9

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Similar questions

Q. Assume that impure copper contains only

F e, A u

and

A g

as impurities. After passage of

140

ampere for

482.5

sec, the mass of anode decreased by

22.260

g and the cathode increased in mass by

22.011

g. Calculate the percentage of iron and percentage of copper originally present.

Q. Assume that impure copper contains iron, gold and silver as impurities. After passing a current of

140

ampere for

482.5

second, the mass of anode decreased by

22.260 g

and the cathode increased in mass by

22.011 g

. Estimate the percentage of iron and copper originally present.

Q. Assume the impure copper contains only iron, silver and a gold as impurities. After passage of 140 A, for 482.5 sec, of the mass of the anode decreased by 22.260 g and the cathode increased in mass by 22.011 g. Estimate the % iron and % copper originally present?

Q. During electrolytic refining of copper.
(a) Pure copper acts as anode.
(b) Pure copper acts as cathode.
(c) Impure copper acts as anode.
(d) Impure copper acts as cathode.

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