Imran deposits Rs. 400 per month in a post office as R.D. for 2 years. If the rate of interest is 12%, find the amount he will receive at the end of 2 years.
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Solution
Amount deposited every month =P=Rs400
T(in\ years) =2=24 months
Rate(R) of interest =12%
∴ total deposit made (T) =112[N(N+1)2]
=112(24×252)
=25 years
Now interest(I) =P×R×T100
=400×25×12100
=Rs1200
∴ total amount due =P×N+I
=(400×24)+1200
=9600+1200
=10800
∴ Imran will receive Rs.10800 at the end of 2years.