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Question

In 0.1 M solution of a non-electolyte , ψwΨ (water potential) value will be

A
zero bar
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B
+ 2.3 bar
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C
-2.3 bar
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D
-22.4 bar
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Solution

The correct option is C -2.3 bar
Water potential of pure water is zero.
As a solute is added, water potential decreases and becomes negative.
Water potential can be calculated as:
ψ (water potential) = ψ P (pressure potential) + ψ S (solute potential)
For the 0.1 M solution of a non electrolyte, ψ P is 0 bar and is ψ S is -2.3 bar
So,
ψ = 0 bar + (-2.3 bar)
ψ = -2.3 bar
So, the correct answer is '-2.3 bar'.

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