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Electrolytes

In 0.1M sol...

Question

In $0.1 M$ solution of salt $K A$ , the anion is $8$ % hydrolysed. What is dissociation constant of $H A$ ?

1.43 \times 10^{- 10}

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1.43 \times 10^{- 11}

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1.43 \times 10^{- 12}

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None of these

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Solution

The correct option is B $1.43 \times 10^{- 11}$
Anion is $8 %$ hydrolysed.
So,
$h$ = $\frac{8}{100}$ = $0.08$
Also, as an anion is hydrolyzed to such a small extent, we say that the acid is weak. Hence, this salt is a Salt of Weak Acid and Strong Base.
$K_{h}$ = $h^{2} C$
= ${0.08}^{2} \times 0.1$
= $6.4 \times 10^{- 4}$
$K_{a}$ = $\frac{K_{w}}{K_{h}}$

= $\frac{10^{- 14}}{6.4 \times 10^{- 4}}$

= $1.5 \times 10^{- 11}$

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h = 2.12 \times 10^{- 2}, K_{h} = 1.43 \times 10^{- 4} M

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