Question

In 1.0 s, a particle goes from point A to point B, moving in a semicircle of radius 1.0 m (see figure). The magnitude of the average velocity is

• A. 3.14 m/s
• B. 2.0 m/s
• C. 1.0 m/s
• D. Zero

Answer 1

Answer: (B)

Step 1: Given that:

A particle goes from point A to B on the semicircular path.

Radius of the path($r$) = $1.0m$

Time taken(t) = $1sec$

Step 2: calculation of the average velocity of the particle:

Average velocity = $\frac{Totaldisplacement}{Toaltimetaken}$

Total displacement= Shortest distance between initial and final point

= Diameter of the semicircle

= $2\times Radiusofsemicircle$

= $2\times 1m$

= $2m$

Thus,

Average velocity= $\frac{2m}{1sec}$

= $2m{s}^{-1}$

Thus,

Option B) $2m{s}^{-1}$ is the correct option.