Question

In $1\text{g}$ of a metal oxide, the amount of metal present is $0.68\text{g}$. What is the equivalent weight of the metal?

• A. $17\text{g}$
• B. $34\text{g}$
• C. $68\text{g}$
• D. $52\text{g}$

Answer 1

The correct option is A $17\text{g}$

Mass of the metallic oxide = $1\text{g}$; mass of the metal = $0.68\text{g}$
Mass of oxygen = mass of oxide - mass of metal
Mass of oxygen $=1–0.68=0.32\text{g}$
Using the oxygen displacement method,
$\frac{\text{weight of the metal}}{\text{weight of oxygen}}=\frac{\text{equivalent weight of the metal}}{\text{equivalent weight of oxygen}}$
Equivalent weight of metal $=\frac{0.68}{0.32}\times 8=17\text{g}$