Question

In $10$ days, the earth picks up $2.6\times {10}^8$ pounds of dust from the atmosphere. How much dust will it pick up in $45$ days? (in terms of multiples of ${10}^8$ pounds)

Answer 1

Given, in $10$ days the earth picks up $2.6\times {10}^8$ pounds of dust from the atmosphere.

So, in $1$ day the earth picks up $\frac{2.6\times {10}^8}{10}$ pounds of dust from the atmosphere.

Then, in $45$ days the earth will pick up $\frac{2.6\times {10}^8\times 45}{10}=11.7\times {10}^8$ pounds of dust from the atmosphere.

So, in terms of multiple of ${10}^8,$ the final answer will be $\mathrm{11.7.}$