In 10 s, a charge of 25 C leaves a battery, and 200 J of energy are delivered to an outside circuit as a result.
(a) What is the p.d. across the battery?
(b) What current flows from the battery?

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Solution

(a) Potential difference, $V = \frac{W}{Q} = \frac{200}{25} = 8 V$

(b) Current, $I = \frac{Q}{t} = \frac{25}{10} = 2.5 A$

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In 10 s, a charge of 25 C leaves a battery, and 200 J of energy are delivered to an outside circuit as a result. (a) What is the p.d. across the battery? (b) What current flows from the battery?

(a) Potential difference, V=WQ=20025=8 V (b) Current, I=Qt=2510=2.5 A

In 10 s, a charge of 25 C leaves a battery, and 200 J of energy are delivered to an outside circuit as a result.
(a) What is the p.d. across the battery?
(b) What current flows from the battery?

(a) Potential difference, $V = \frac{W}{Q} = \frac{200}{25} = 8 V$

(b) Current, $I = \frac{Q}{t} = \frac{25}{10} = 2.5 A$