In 10 seconds a charge of 25 coulomb leaves a battery and 200 joules of energy are delivered to an outside circuit as a result.what is the potential difference across the battery?

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Solution

Q=25
t=10
I=Q/t=25/10
ie,I=2.5
E=200j
E=IV
200=2.5V
V=80v

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In 10 seconds a charge of 25 coulomb leaves a battery and 200 joules of energy are delivered to an outside circuit as a result.what is the potential difference across the battery?

Q=25 t=10 I=Q/t=25/10 ie,I=2.5 E=200j E=I*V​​​​​ 200=2.5*V V=80v ​​

Q=25
t=10
I=Q/t=25/10
ie,I=2.5
E=200j
E=IV
200=2.5V
V=80v