In 10 years, A will be twice as old as B was 10 years. ago. If A is now 9 years older than B, the present age of B is:

19 years

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29 years

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39 years

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49 years

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59 years

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Solution

The correct option is C
39 years

Let B's present age = x years.

Then, A's present age = (x + 9) years

$∴ (x + 9) + 10 = 2 (x - 10) \Leftrightarrow x + 19 = 2 x - 20 \Leftrightarrow x = 39$

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In 10 years, A will be twice as old as B was 10 years. ago. If A is now 9 years older than B, the present age of B is:

The correct option is C 39 years Let B's present age = x years. Then, A's present age = (x + 9) years ∴(x+9)+10=2(x−10)⇔x+19=2x−20⇔ x=39

The correct option is C
39 years

Let B's present age = x years.

Then, A's present age = (x + 9) years

$∴ (x + 9) + 10 = 2 (x - 10) \Leftrightarrow x + 19 = 2 x - 20 \Leftrightarrow x = 39$