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Question

in 10ml ; pH=4 solution 990ml of .2M NaCl solution is added the pH of resulting solution will be??

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Solution

NaCl is a salt. So it will not contribute to pH of the solution.

Volume of the solution = 10 ml
pH= 4
- log [H+] = 4
[H+] = A.log (-4)
= 1 x 10-4
Volume of the new solution = Volume of the original solution + volume of the added NaCl
= 10 + 990 = 1000 ml
[H+] of the new solution = [H+] of the original solution + [H+] of the NaCl solution
= 1 x 10-4 + 0 = 1 x 10-4
Molarity of the new solution = ​1 x 10-4 / 1000 = 1 x 10-7
pH= -log [H+]
= - log ​1 x 10-7
= 7

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