Question

In $16$ throws of a die getting an even number is considered a success, then the variance of the success is

• A. $4$
• B. $6$
• C. $2$
• D. $256$

Answer 1

Answer: (A)

$4$

Probability of getting even number on throwing dice is $p=\frac{1}{2}$, which is probability of success

And probability of failure is $,q=1-p=\frac{1}{2}$

Hence variance in $16$ throws is $=npq=16\cdot \frac{1}{2}\cdot \frac{1}{2}=4$