Question

In $20mL$ of a solution of $HCl,3g$ of $CaC{O}_3$ were dissolved, $0.5g$ of $CaC{O}_3$ being left undissolved. Find out the strength of this solution in terms of (i) Normality and (ii) $g/L$. Find the volume of this acid which would be required to make $1litre$ of normal solution of this acid.

Answer 1

Volume of HCl = 20 ml

Amount of $CaC{O}_3$ dissolve = 2.5g

Normality = $\frac{gramequvi}{volume}=\frac{2.5\times 1000}{50\times 20}=2.5N$

Strength = Normality$\times$ equivalent weight = $2.5\ast 50=125g/L$

Normality = 2.5N

Now,

$N_1{V}_1=N_2{V}_2$

$2.5\ast V_1=1\ast 1$

$V_1=0.4Lor400ml$

So, volume of acid require = $400ml$