In $2001$ , the world's population was $250000$ . With a growth rate of approximately $14 %$ , what was the population in $2011$ ?

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Solution

Given, $P = 250000, r = 14 %, n = 10$ years
We need to find amount $A$ .
We know, $A = P [{(1 + \frac{r}{100})}^{n}]$
$A = 250000 [{(1 + \frac{14}{100})}^{10}]$
$= 926800$
Hence, the population of the city after $10$ years $= 926800$ .

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In 2001, the world's population was 250000. With a growth rate of approximately 14%, what was the population in 2011?

Given, P=250000,r=14%,n=10 yearsWe need to find amount A.We know, A=P[(1+r100)n]A=250000[(1+14100)10]=926800Hence, the population of the city after 10 years =926800.

In $2001$ , the world's population was $250000$ . With a growth rate of approximately $14 %$ , what was the population in $2011$ ?

Given, $P = 250000, r = 14 %, n = 10$ years
We need to find amount $A$ .
We know, $A = P [{(1 + \frac{r}{100})}^{n}]$
$A = 250000 [{(1 + \frac{14}{100})}^{10}]$
$= 926800$
Hence, the population of the city after $10$ years $= 926800$ .