In $3$ mins a total charge of $108$ C flows through a bulb when it is connected to a cell. Find the electric current flowing through the bulb.

36 A

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0.6 A

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1.8 A

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None

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Solution

The correct option is C $0.6 A$
Charge flowing through bulb in $3$ min $= 108$ C
So, charge flowing in $1$ sec= $\frac{108}{3 \times 60} = 0.6 A$
or, $I = \frac{Q}{t}$ , $I = \frac{108 C}{60 \times 3} = 0.6 A$

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