In 5s, a charge of 25C leaves a battery, and 100 J of energy are delivered to an outside circuit. What is the potential difference across the battery?

20V

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125V

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Solution

The correct option is C 4V
Answer is C.
Here, the time taken t is 5 seconds, amount of charge q is 25 C and the work done w is 100 J.
We know that, the current I = Amount of charge/Time taken.
That is, I = q / t, 25/5 = 5 A.
Work done = Energy dissipated = Pt or $V I \times t a s P = V I$ .
Therefore,
W = VIt.
So, 100 = V55.
V = 100/25 = 4 V.
Hence, the potential difference across the battery is 4 V.

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