Question

In ${}_{88}R{a}^{226}$ nucleus there are

• A. $226$ protons and $88$ electrons
• B. $138$ protons and $88$ neutrons
• C. $226$ neutrons and $138$ electrons
• D. $138$ neutrons and $88$ protons

Answer 1

The correct option is D $138$ neutrons and $88$ protons

${}_{88}R{a}^{226}$; No. of protons $=88$

No. of neutrons $=226-88=138$