Question

In a 2-digit number, the face value of the digit in the tens place is double the face value of the digits in the ones place. If the sum of the two face values is 12, find the 2-digit number.

Answer 1

Dear student,

Let the two digit number be 10x + y
Given that the face value of the digit in the tens place is double the face value of the digit in the ones place.

$\Rightarrow x=2y\cdots \left(i\right)$
And sum of the two face values is 12.

$\Rightarrow x+y=12\cdots \left(ii\right)$
Putting value of x from equation (i) in equation (ii), we get
$2y+y=12\Rightarrow 3y=12\Rightarrow y=\frac{12}{3}=4$
From $\left(i\right),x=2y=2\times 4=8$
Therefore, two digit number is $10\times 8+4=80+4=84$.

Regards