Question

In a $2$ digit number, the units place digit is $x$. If the sum of digits be $9$, then the number is $(10x–9)$. State whether the statement is true (T) or false (F).

• A. True
• B. False

Answer 1

The correct option is B False

Estimate the expression for the digit:

Given, The units place digit is $x$.

The Sum of the digits is $9$.

Therefore, the tens digit $=9-\mathrm{x}$.

We know that for a number with ten's place digits $\mathrm{a}$ and units place digit $\mathrm{b}$, can be written as$10\mathrm{a}+\mathrm{b}$

Here, $\mathrm{b}=\mathrm{x}$ and $\mathrm{a}=9-\mathrm{x}$

Therefore that number can be written as,

$10\left(9-x\right)+x=90-10x+x$

$=90-9x$

Hence, the given statement is false.