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Question

In a 2 L flask, the reaction takes place as:
COCl2(g)CO(g)+Cl2(g)
The equilibrium concentration of [COCl2] was found to be 0.4 M. If an excess of COCl2 is added to the system, the equilibrium reestablishes and [COCl2] becomes 1.6 M. What is the equilibrium concentration of [CO]?

A
Half of the former value
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B
Thrice of the former value
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C
Remains unaltered
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D
Twice of the former value
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Solution

The correct option is D Twice of the former value
The given reaction is,
COCl2(g)CO(g)+Cl2(g)
Kc=[CO][Cl2][CoCl2]

Let, [CO]=x, then also [Cl2]=x
Kc=x2[CoCl2]=x24

Again, Kc=x20.4=[CO][Cl2][CoCl2]
x20.4=[CO]21.6
x2×4=[CO]2
2x=[CO]

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