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Question

In a 3.2 Kbp long piece of DNA, 820 adenine bases were found. What would be the number of cytosine bases?

A
780
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B
1560
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C
740
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D
1480
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Solution

The correct option is: A

Explanation of the correct option:
In the given piece of DNA, The total number of bases adenine, thymine, cytosine and guanine is 3.2Kbp which is equal to 3200 base pairs.
i.e., A+T+C+G = 3200
or, (A+T) + (C+G) = 3200
or, 2A + 2C = 3200 since bp of A=T and C=G
or, A + C = 1600
or, C = 1600 - A = 1600 - 820
or, C = 780
So, the number of cytosines will be 780 bps.

Explanation of the incorrect option:

Option B: the number of cytosines will be 780 bps.

Option C: the number of cytosines will be 780 bps.

Option D: the number of cytosines will be 780 bps.

Final answer: In a 3.2 Kbp long piece of DNA, 820 adenine bases were found. The number of cytosine bases is 780.


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