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Question
In a 4− digit number 2 digits are repeated, not consecutively. If the value of 5 at the hundreds place is subtracted from the value of the digit at the thousands place, the result is 6,500. Determine the number.
(More than one correct answer)
In a 4− digit number 2 digits are repeated, not consecutively. If the value of 5 at the hundreds place is subtracted from the value of the digit at the thousands place, the result is 6,500. Determine the number.
(More than one correct answer)
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Solution
The correct option is B Seven thousand five hundred seventy-five
The number is a 4− digit number.
In a 4− digit number 2 digits are repeated, not consecutively.
The value of 5 at the hundreds place in the number will be 5×100=500.
This 500 is subtracted from the value of the digit at the thousands place and gives 6,500.
The value at the thousands place should be 500+6,500=7,000.
So the digit at the thousands place is 7 and our other digit is 5.
Let us form the 4− digit number in which 5 and 7 will not repeat consecutively.
The only way in which 5 and 7 will not repeat consecutively is 7,575.
The word form of 7,575 is seven thousand five hundred seventy-five.
Hence options a is the correct answer.
The number is a 4− digit number.
In a 4− digit number 2 digits are repeated, not consecutively.
The value of 5 at the hundreds place in the number will be 5×100=500.
This 500 is subtracted from the value of the digit at the thousands place and gives 6,500.
The value at the thousands place should be 500+6,500=7,000.
So the digit at the thousands place is 7 and our other digit is 5.
Let us form the 4− digit number in which 5 and 7 will not repeat consecutively.
The only way in which 5 and 7 will not repeat consecutively is 7,575.
The word form of 7,575 is seven thousand five hundred seventy-five.
Hence options a is the correct answer.
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