In a 45-45-90- triangle- the length of the hypotenuse is 9 -2- What is the length of its sides-

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Standard IX

Mathematics

Division of Numbers with Square Roots

In a 45∘-45∘-...

Question

In a $45^{\circ} - 45^{\circ} - 90^{\circ}$ triangle, the length of the hypotenuse is $9 \sqrt{2}$ . What is the length of its sides?

$8 u n i t s$

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$6 u n i t s$

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$9 u n i t s$

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$7 u n i t s$

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Solution

The correct option is C
$9 u n i t s$

Let the length of the equal side be 'x'.
According to pythagoras theorem,
$x^{2} + x^{2} = (9 \sqrt{2})^{2} \to 2 x^{2} = 162 \to x^{2} = 81 \to x = 9$

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In a 45∘−45∘−90∘ triangle, the length of the hypotenuse is 9√2. What is the length of its sides?

The correct option is C 9 units Let the length of the equal side be 'x'. According to pythagoras theorem, x2+x2=(9√2)2→2x2=162→x2=81→x=9

In a $45^{\circ} - 45^{\circ} - 90^{\circ}$ triangle, the length of the hypotenuse is $9 \sqrt{2}$ . What is the length of its sides?

The correct option is C
$9 u n i t s$

Let the length of the equal side be 'x'.
According to pythagoras theorem,
$x^{2} + x^{2} = (9 \sqrt{2})^{2} \to 2 x^{2} = 162 \to x^{2} = 81 \to x = 9$