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Question
In a 68 nm long DNA molecule, Adenine constitutes 25%. How many hydrogen bonds would be present between the strands?(Average length of a nucleotide is 3.4 Angstroms)
In a 68 nm long DNA molecule, Adenine constitutes 25%. How many hydrogen bonds would be present between the strands?(Average length of a nucleotide is 3.4 Angstroms)
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Solution
The correct option is A 250
- As the average length of a nucleotide is 3.4 Angstrom hence there are 200 nucleotides present in 68 nm long DNA. 2 nucleotides form a base pair hence 100 base pairs are present. Adenine-Thymine forms a base pair with a double hydrogen bond and Guanine-Cytosine form base pair with a triple bond.
- According to the question, 25% of this DNA molecule consists of Adenine which means that equal percent of Thymine is present as well forming 50% DNA as Adenine-Thymine base pair ( 50 base pairs) While Rest of the 50% DNA consists of Guanine -Cytosine ( 50 base pairs ).
Based on this number of hydrogen bonds present are -2*50 + 3*50 = 250.- So, the correct option is '250'.
- As the average length of a nucleotide is 3.4 Angstrom hence there are 200 nucleotides present in 68 nm long DNA. 2 nucleotides form a base pair hence 100 base pairs are present. Adenine-Thymine forms a base pair with a double hydrogen bond and Guanine-Cytosine form base pair with a triple bond.
- According to the question, 25% of this DNA molecule consists of Adenine which means that equal percent of Thymine is present as well forming 50% DNA as Adenine-Thymine base pair ( 50 base pairs) While Rest of the 50% DNA consists of Guanine -Cytosine ( 50 base pairs ).
Based on this number of hydrogen bonds present are -
2*50 + 3*50 = 250.
- So, the correct option is '250'.
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