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Arithmetic Progression

In a ABC , ∠ ...

Question

In a ∆ABC, ∠A = x°, ∠B = 3x° and ∠C = y°. If 3y − 5x = 30, prove that the triangle is right angled.

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Solution

We have to prove that the triangle is right

Given and

Sum of three angles in triangle are

By solving with we get,

Multiplying equation by 3 we get

Subtracting equation from

Substituting in equation we get

Angles and are

A right angled triangle is a triangle in which one side should has a right angle that is in it.

Hence, The triangle ABC is right angled

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Similar questions

△ A B C, ∠ A = x, ∠ B = 3 x

∠ C = y

3 y - 5 x = 30

, then prove that the triangle is right angled triangle.

In a $△ A B C, ∠ A = x^{\circ}, ∠ B = (3 x - 2)^{\circ}, ∠ C = y^{\circ}$ . If 3y – 5x = 30. Prove that the triangle is right angled.

∆ A B C, ∠ A = x °, ∠ B = (3 x) ° and ∠ C = y ° .

3 y - 5 x = 30,

show that the triangle is right-angled.

Δ A B C, ∠ A = x^{\circ}, ∠ B = 3 x^{\circ}

∠ C = y^{\circ} .

5 x - 3 y + 30 = 0,

then prove that it is a right angled.

Δ A B C, ∠ A = x^{o}, ∠ B = 3 x^{o}

∠ C = y^{o}

3 y^{o} - 5 x^{o} = 30^{o}

, then the triangle is

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