In a ∆ABC, AD is the bisector of ∠BAC. If AB = 6 cm, AC = 5 cm and BD = 3 cm, then DC =

(a) 11.3 cm
(b) 2.5 cm
(c) 3 : 5 cm
(d) None of these

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Solution

Given: In a ΔABC, AD is the bisector of . AB = 6cm and AC = 5cm and BD = 3cm.

To find: DC

We know that the internal bisector of angle of a triangle divides the opposite side internally in the ratio of the sides containing the angle.

Hence,

Hence we got the result

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In a $Δ A B C$ , AD is the bisector of $∠ A$ , meeting side BC at D.
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