In a ∆ABC, if AB = AC and ∠B = 65°, find ∠C and ∠A.

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Solution

$In ∆ ABC, AB = AC \Rightarrow ∠ ABC = ∠ ACB ∴ ∠ ACB = 65 ° Let ∠ A be x ° . Now, ∠ A + ∠ B + ∠ C = 180 ° \Rightarrow x + 65 ° + 65 ° = 180 ° \Rightarrow x = 180 ° - 130 ° \Rightarrow x = 50 ∴ ∠ C = 65 ° and ∠ A = 50 °$

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