Question

In a ∆ABC it is given that base = 12 cm and height = 5 cm. Its area is
(a) 60 cm²
(b) 30 cm²
(c) $15\sqrt{3}{\mathrm{cm}}^2$
(d) 45 cm²

Answer 1

(b) 30 cm²

$$\begin{gathered} \mathrm{Area}\mathrm{of}\mathrm{triangle}=\frac{1}{2}\times \mathrm{Base}\times \mathrm{Height} \\ \mathrm{Area}\mathrm{of}\mathit{}\mathit{∆}ABC=\frac{1}{2}\times 12\times 5=30{\mathrm{cm}}^2 \end{gathered}$$