In a biaxial strain system εxandεy, what is the maximum engineering shearing strain?
εx+εy
εx−εy
εx+εy2
ϕx′y′2=−(εx−εy2)sin2θ+ϕxy2cos2θ
For θ=45∘and ϕxy=0
⇒ϕx′y′2=−(εx−εy2)
⇒ϕx′y′=−(εx−εy)
⇒ϕx′y′=εx−εy (magnitude)