In a binary star system, two stars of masses m and 2m distance r apart are revolving about their common centre of mass under their mutual gravitational attraction.

The ratio of angular momenta of two star about centre of mass is

2:1

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1:2

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1:1

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1:4

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Solution

The correct option is A
2:1

$\frac{L_{1}}{L_{2}} = \frac{m_{1} r_{1}^{2} ω}{m_{2} r_{2}^{2} ω},$ where $r_{1}$ and $r_{2}$ are respective distances from COM, such that $m_{1} r_{1} = m_{2} r_{2}$

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In a binary star system, two stars of masses m and 2m distance r apart are revolving about their common centre of mass under their mutual gravitational attraction. The ratio of angular momenta of two star about centre of mass is

The correct option is A 2:1 L1L2=m1r21ωm2r22ω, where r1 and r2 are respective distances from COM, such that m1r1=m2r2

In a binary star system, two stars of masses m and 2m distance r apart are revolving about their common centre of mass under their mutual gravitational attraction.

The ratio of angular momenta of two star about centre of mass is

The correct option is A
2:1

$\frac{L_{1}}{L_{2}} = \frac{m_{1} r_{1}^{2} ω}{m_{2} r_{2}^{2} ω},$ where $r_{1}$ and $r_{2}$ are respective distances from COM, such that $m_{1} r_{1} = m_{2} r_{2}$