In a binary symmetric channel the crossover probabilities of the channel is given as 0.2, then the maximum mutual information of the channel is equal is equal to ________ bits/symbol.
0.278

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Solution

The correct option is A 0.278
$The maximum value of mutual information is equal to the channel capacity. If the crossover probability are given as 0.2; then the transmission probabilities are 1 - 0.2 = 0.8 \begin{matrix} C & = 1 + p {log}_{2} p + (1 - p) {log}_{2} (1 - p) = 1 + (0.8) {log}_{2} (0.8) + (0.2) {log}_{2} (0.2) = 0.278 \end{matrix}$

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In a binary symmetric channel the crossover probabilities of the channel is given as 0.2, then the maximum mutual information of the channel is equal is equal to ________ bits/symbol.0.278

The correct option is A 0.278 The maximum value of mutual information is equal to the channel capacity.If the crossover probability are given as 0.2; then the transmission probabilities are 1 - 0.2 = 0.8C=1+plog2p+(1−p)log2(1−p)=1+(0.8)log2(0.8)+(0.2)log2(0.2)=0.278

In a binary symmetric channel the crossover probabilities of the channel is given as 0.2, then the maximum mutual information of the channel is equal is equal to ________ bits/symbol.
0.278