In a binomial distribution consisting of 5 independent trials, the probability of 1 and 2 successes are 0.4096 and 0.2048 respectively. The parameter p of the distribution is
A
1/3
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B
1/4
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C
1/5
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D
1/6
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Solution
The correct option is B1/5 In a binomial distribution consisting of 5 independent trials, n = 5 The probability of 1 and 2 successes are 0.4096 and 0.2048 respectively. 5C1p1(1−p)5−1=0.40965C2p2(1−p)5−2=0.2048 5p(1−p)4=0.4096 _____ (1) 10p2(1−p)3=0.2048 ______ (2) Divide equation (1) by (2), we get (1−p)2p=2