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Question

In a binomial distribution consisting of 5 independent trials, the probability of 1 and 2 successes are 0.4096 and 0.2048 respectively. The parameter p of the distribution is

A
1/3
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B
1/4
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C
1/5
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D
1/6
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Solution

The correct option is B 1/5
In a binomial distribution consisting of 5 independent trials, n = 5
T
he probability of 1 and 2 successes are 0.4096 and 0.2048 respectively.
5C1p1(1p)51=0.4096 5C2p2(1p)52=0.2048
5p(1p)4=0.4096 _____ (1) 10p2(1p)3=0.2048 ______ (2)
Divide equation (1) by (2), we get
(1p)2p=2

5p=1

p=15

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