Standard Deviation about Mean for Continuous Frequency Distributions
In a binomial...
Question
In a binomial distribution n=200,p=0.04. Taking Poisson distribution as an approximation to the binomial distribution . Assertion (A) :- Mean of the Poisson distribution =8 Reason (R) : In a Poisson distribution, P(X=4)=5123e8
A
both A and R are true and R is the correct explanation of A
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
both A and R are true and R is not correct explanation of A
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
A is true but R is false
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
A is false but R is true
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C both A and R are true and R is not correct explanation of A mean of P.D. =np=8 And P(X=4)=e−8(8)44!=5123e8 Hence both statement are correct but they are not related to each other.