Question

In a binomial distribution $n=9$ and $p=\frac{1}{3}$.The mode of the binomial distribution is

• A. $3$
• B. $4$
• C. $3$ and $4$
• D. $3.5$

Answer 1

Answer: (A)

$3$

$(n+1)p$
$=10\left(\frac{1}{3}\right)$

$=3.33$
Hence, no integral.
Therefore mode is $\left[3.33\right]$ where, $\left[x\right]$ is the greatest integer function.
Hence mode is $3$.