In a binomial distribution- the probability of getting a success is 14 and the standard deviation is 3- Then its mean is- Eamcet 2002

The correct option is A 12 Hence, p=14 Therefore,Variance =S.D^2 np(1 p)=9 n(14)(34)=9 n=3(16) n=48 Hence, Mean =np ...

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Standard XII

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Standard Deviation about Mean for Continuous Frequency Distributions

In a binomial...

Question

In a binomial distribution, the probability of getting a success is $\frac{1}{4}$ and the standard deviation is $3$ . Then its mean is. (Eamcet 2002)

12

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Solution

The correct option is A $12$
Hence, $p = \frac{1}{4}$
Therefore,
Variance $= S . D^{2}$
$n p (1 - p) = 9$
$n (\frac{1}{4}) (\frac{3}{4}) = 9$
$n = 3 (16)$
$n = 48$
Hence, Mean $= n p$
$= \frac{48}{4}$
$= 12$

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In a binomial distribution, the probability of getting a success is 14 and the standard deviation is 3. Then its mean is. (Eamcet 2002)

The correct option is A 12Hence, p=14Therefore,Variance=S.D2np(1−p)=9n(14)(34)=9n=3(16)n=48Hence, Mean=np=484=12

In a binomial distribution, the probability of getting a success is $\frac{1}{4}$ and the standard deviation is $3$ . Then its mean is. (Eamcet 2002)

The correct option is A $12$
Hence, $p = \frac{1}{4}$
Therefore,
Variance $= S . D^{2}$
$n p (1 - p) = 9$
$n (\frac{1}{4}) (\frac{3}{4}) = 9$
$n = 3 (16)$
$n = 48$
Hence, Mean $= n p$
$= \frac{48}{4}$
$= 12$